The following is a tutorial question from my teacher.
A transmitter requires the IM3 products to be -65dB below the main tones when the total output power is 20 dBm. Calculate the output IP3 of this transmitter.
This is what I think.
The output IP3 is the third-order intercept point, which is the input power level at which the third-order intermodulation distortion (IM3) products are 30 dB below the main tones. In this case, the IM3 products are -65 dB below the main tones,
$$OIP3[dBm] = P1 [dBm] + \frac{\Delta P [dBc]} {2} = 62.5 dBm$$
$$OIP3 = 30dBm + \frac{65 dB} {2} = 62.5 dBm$$
But the book give me 49.5 \$dBm\$.