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Pushing a cylinder through the water with an angular velocity of $\omega$.

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The cylinder diameter and length are $D$ and $L$ respectively and the length from the rotation point to the center of the cylinder is $L_{arm}$.

$F_D = \frac{1}{2} \cdot \rho \cdot C_D \cdot A \cdot v^2 $

But how do I find the drag coefficient?

Babar
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1 Answers1

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There are tables for common shapes, e.g. in my fluid mechanics formulary I find for a long cylinder $C_\text{D}=0.3 \dots 1.3$ depending on the Re-Number.

Dominik Kern
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